Question

help 2 a medal

Answer 1

You are correct.

Answer 2

y=kx^2
28=k*2^2
63=k*3^2
what k can be ?

Answer 3

im not sure im correct

Answer 4

\[(\frac{ 3 }{ 2 })^2=\frac{ 9 }{ 4 }=\frac{ 9 }{ 4 }\times \frac{ 7 }{ 7 }=\frac{ 63 }{ 28 }\]
\[4^2=16*7=112\]
clearly k=7