Question

can someone help me with this equation i'm supposed to simplify it
(3^ √6*4√ 6)^12

Answer 1

see your question again.

Answer 2

What you mean by ^ that symbol

Answer 3

the 3 is and exponent so i put that sign to mean the 3 is an exponent

Answer 4

am i correct?
\[\left( 3^{\sqrt{6}}*4^{\sqrt{6}}\right)^{12}\]

Answer 5

the 3 and 4 is supposed to be the smaller numbers and the number 6 is supposed to be big and the 12 is correct

Answer 6

is it
\[\left( \sqrt[3]{6} *\sqrt[4]{6}\right)^{12}\] ?

Answer 7

yes thats the equation

Answer 8

if so then
\[=\left( 6^{\frac{ 1 }{ 3 }}*6^{\frac{ 1 }{ 4 }} \right)^{12}\]
\[=\left( 6^{\frac{ 1 }{ 3 }+\frac{ 1 }{ 4 }} \right)^{12}=\left( 6^{\frac{ 4+3 }{ 12 }} \right)^{12}=6^7\]

Answer 9

how did you get rid of the square root symbol

Answer 10

That not square root that means 6 raise to the power 1/3 and 1/4

Answer 11

\[\sqrt[n]{x}=x ^{\frac{ 1 }{ n }}\]

Answer 12

\[\sqrt{x}=x ^{\frac{ 1 }{ 2 }}\]

Answer 13

So when when you add 1/3 and 1/4
You will get 7/12 means
6 raised to the power 7/12 .

Answer 14

Also there is whole power 12
So multiply 7/12 and 12
So you got 7 means the final
Answer is 6^7.

Answer 15

ok i think i got it thanks for helping me