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OpenStudy (anonymous):
@surjithayer
OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
1 belongs to the list containing 1 ?
yeah it does...
or did you mean
1 \(\in\) I ?
where I is an Integer set?
OpenStudy (anonymous):
If you cant read the latex i dont know why it showed up before \(\in\) = E
OpenStudy (freckles):
The element in question is {1}
is the element {1} contained in the set containing 1?
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OpenStudy (anonymous):
no
OpenStudy (freckles):
then you have your answer
what if it was
\[\left\{ 1 \right\} \in \left\{ \left\{ 1 \right\} \right\}\]
true or false
OpenStudy (anonymous):
true, funny thing is is i have that problem too
OpenStudy (freckles):
lol
that is funny
hartnn (hartnn):
freckles is the author of the problems you're practicing :P
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OpenStudy (anonymous):
wow this class im in i already marked {1} \(\in\) {1} as false i forgot i was checking my answer that quick,
on this one though {{1}} \(\subsetq\) {1, {1}} is false
OpenStudy (anonymous):
i have no idea why that did not work...
subsetq
OpenStudy (anonymous):
...
OpenStudy (anonymous):
ok now its working again
hartnn (hartnn):
right, thats false
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