Question

please help need to show my work a) graph x+3y< ( theres a line under that symbol), indicating the solution set with crosshatchimg or shading b) explain how you determined which line to draw c) explain how you determined where to shade the solution set

Answer 1

theres a 6 after that symbol forgot to type it

Answer 2

@AlexandervonHumboldt2

Answer 3

Basically you want to draw a graph on line x+3y-6<0.
.. Huh..?

Answer 4

the line under the symbol means include that boundary

Answer 5

do you know how to plot the graph?

Answer 6

@@FibonacciChick666

Answer 7

@FibonacciChick666

Answer 8

a) graph \(x+3y\le6\) indicating the solution set with crosshatchimg or shading b) explain how you determined which line to draw c) explain how you determined where to shade the solution set

Answer 9

yes that it and there is a graph

Answer 10

ok, so do me a favor. First, solve x+3y=6 for y

Answer 11

do i minus 3 from each side?

Answer 12

no, that won't do anything. You have to reverse the order of operations on the y term.

Answer 13

its plus so wouldn't it be minus?

Answer 14

tutorial, here https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-slope/v/converting-to-slope-intercept-form

Answer 15

you want y by itself, if you subtract 3 from both sides, you get x+3y-3=3

Answer 16

so i divide?

Answer 17

not yet, first you need to see if there is any addition or subtraction

Answer 18

I mean you could, but dividing isn't the easiest way at the moment

Answer 19

im confused so add?

Answer 20

so SadMep

Answer 21

You know PEMDAS right?

Answer 22

not really

Answer 23

ok, watch that video then. There is some serious background info needed in order to even comprehend how to do this. This is algebra II, what are you doing it? Aren't you in general math 7 or 8?

Answer 24

i dont even really know i have to submit a paper in the morning linear equations and inequalities

Answer 25

... well, hum, you got some issues.

Answer 26

can you give me the exact prompt/directions. I won't be able to teach you everything, but I can give you the resources to do it

Answer 27

ok this is hard

Answer 28

it's way above your level. You haven't even had algebra yet, right?

Answer 29

its exactly what i posted to begin with

Answer 30

you said a paper, that prompt is not a paper

Answer 31

its unit 7 part 2

Answer 32

ok, step 1: Learn how to solve a linear equation going from standard form to slope intercept(This will be the hardest part)
Step 2: memorize rules for inequalities so you can solve those too(there's only one difference)
Step 3: graph said line once in slope intercept
step 4: Pick a point and plug it into your equation. If it works, shade that side of the graph, if not, the other. Since the inequality is less than or equal to, shade the line.

Answer 33

Telling me the unit does nada for me to help ya

Answer 34

ok well im going to try then thank u

Answer 35

sorry, but I have to be up early, so I can't walk you through. Maybe post another question and get someone to explain "How to put a leaner equation into slope intercept form?"

Answer 36

k thank u

Answer 37

@mehek

Answer 38

@Mehek14

Answer 39

@dtan5457