Question

how do i solve 2x^2+11=29 ?

Answer 1

first take 29 to the other side of the equation

Answer 2

done

Answer 3

subtract 11 both sides

Answer 4

set it up equal to 0 right?

Answer 5

then divide with 2 both sides

Answer 6

so now you have 2x^2+11-29=0
2x^2-18=0
2(x^2-9)=0
Factorize it...

Answer 7

whom ur following arbyj

Answer 8

lovelarap

Answer 9

i got 2(x+3)(x-3)

Answer 10

Your Right!
solve for x now

Answer 11

There is another method of not using "factoring."

Answer 12

i got -3,3

Answer 13

You can give the credit to Lovelarap, I'll show you afterwards if you want.

Answer 14

or x=-3 & x=3

Answer 15

the order doesn't matter @arbyj

Answer 16

as long it's x=-3 and x=3.

Answer 17

@Zenmo factoring is the unit we're learning

Answer 18

Oh, I see didn't see it in your original post. :)

Answer 19

yep

Answer 20

i didn't specify, i apologize

Answer 21

\[2x^2+11=29\]
\[2x^2=18\]
\[x^2=9\]
\[x = (+/-) \sqrt{9}\]
Squaring it will give you two answers: x = -3 & x = 3.

Answer 22

Another short method

Answer 23

thank you! @Lovelarap

Answer 24

your welcome

Answer 25

thank you @Zenmo (: