Question

Seth is using the figure below to prove the Pythagorean Theorem using triangle similarity:
In the given triangle ABC, angle A is 90 degrees, and segment AD is perpendicular to segment BC.

Answer 1

Which of these could be a step to prove BC^2=AB^2+AC^2?
A. By the cross products property, AB^2 = BC multiplied by BD.
B. By the cross products property, AC^2 = BC multiplied by BD
C. By the cross products property, AC^2 = BC multiplied by AD.
D. By the cross products property, AB^2= BC multiplied by AD.

Answer 2

@ganeshie8 @mathstudent55

Answer 3

@calcmathlete

Answer 4

help!!!!