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Fill in the blank to make the expression a perfect square. v^2-6v+?
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\[v(v^2/v+−6v/v)\] simplify each term in parentheses: \[v(v-6)\]
can you explain further? @AnitaS.
Hey Kelly :) \(\large\rm v^2\color{orangered}{-6v}\quad=v^2\color{orangered}{-3v-3v}\) If you split the middle term in half like this, you can determine that the missing piece that we need is (-3)*(-3)
It actually told me the answer was 9.
@KellyRJr yes, -3*-3 = 9 sorry if you didn't understand that.
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