What is the mass, in grams, of a sample of 6.98 × 1024 atoms of magnesium (Mg)? Show your work or explain the steps that you used to determine your answer.

Question

photon336 · Answer

24.305 amu is the mass of magnesium. 

Now one mole of magnesium contains 6.02x10^23 particles of magnesium. this is called avogadros number, and what this means is that 1 mole of any substance will contain 6.02x10^23 particles. 

so in essence 24.304 grams of magnesium contains 6.02x10^23 particles. 

so to do this we must set up a proportion and on the other side we place the mass in the numerator and the number of atoms in the denominator to be consistent. 

then we solve for x. if you do this you should be able to get the mass of magnesium in that sample. 

$$\frac{ 24.304g }{ 6.02x10^{23} atoms } = \frac{ x }{ 6.98x10^{24} atoms }$$

photon336 · Answer

you get the idea right?

photon336 · Answer

This is all based off of avogadro's number