Question

Help please

Answer 1

x/x+5=x-4/x

Answer 2

@xapproachesinfinity

Answer 3

i am going to guess that this is \[\frac{x}{x+5}=\frac{x-4}{x}\] is that correct?

Answer 4

Yes

Answer 5

then since \[\frac{a}{b}=\frac{c}{d}\iff ad =bc\] start wotj \[x^2=(x-4)(x+5)\] and solve that one

Answer 6

*with

Answer 7

Yes i agree with that
then after expanding the equation i got
x^2=x^2+x-20

Answer 8

I can not go further than that

Answer 9

subtract \(x^2\) from both sides

Answer 10

Okay i think i can take it from here
But hold on to check if am correct

Answer 11

ok

Answer 12

x=20

Answer 13

Am i correct

Answer 14

i think so
you want to check it?

Answer 15

yes

Answer 16

\[\frac{x}{x+5}=\frac{x-4}{x}\] put \(x=20\) get \[\frac{20}{20+5}=\frac{20-4}{20}\]

Answer 17

or \[\frac{20}{25}=\frac{16}{20}\] true or false?

Answer 18

true

Answer 19

then you are right

Answer 20

4/5 in both sides

Answer 21

zactly

Answer 22

Thanks

Answer 23

yw