Question

Physics,

https://www.dropbox.com/s/cksxgt4v5h1atoi/Screenshot%202016-01-14%2018.35.25.png?dl=0

Is my answer of V = -1 m/s correct ??

Answer 1

You start with 6 x 4 = 24 kg m/s of momentum to the right.
After exploding one of the fragments is carrying 2 x 8 = 16 kg m/s of momentum to the right.
So the other fragment of mass 6 - 2 = 4 kg must be carrying 24 - 16 = 8 kg m/s of momentum to the right.

So the answer to your question is "No, you do not have the correct answer."

Answer 2

I am asked to find the velocity ...

Answer 3

we have to apply the conservation of momentum, so we can write this equation:
\[\Large m{v_0} = {m_1}{v_1} + {m_2}{v_x}\]
where \(v_x\) is the x-component of the velocity of the secon fragment, furthermore, we have no y-component of the total momentum. Therefore, substituting numeric data, we have:
\[\Large 6 \cdot 4 = 2 \cdot 8 + \left( {6 - 2} \right){v_x}\]
Finally, I have supposed that the total mass is conserved