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OpenStudy (thehollywoodstud):
OpenStudy (thehollywoodstud):
THE FIRST ONE IS NQ
jhonyy9 (jhonyy9):
so than there is triangle RST similar triangle NPQ
so these mean that side RS similar side NP
--------------------ST ---------- PQ
--------------------RT ---------- ?
OpenStudy (thehollywoodstud):
#2 is 10?
OpenStudy (thehollywoodstud):
nq??
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OpenStudy (thehollywoodstud):
ok sweet can u help me with #2
jhonyy9 (jhonyy9):
for second 10 is right sure
OpenStudy (thehollywoodstud):
its ok
OpenStudy (thehollywoodstud):
can i get help with some more?
OpenStudy (thehollywoodstud):
10?
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OpenStudy (thehollywoodstud):
ok can u help me with this one
OpenStudy (thehollywoodstud):
can u help me @jhonyy9
OpenStudy (thehollywoodstud):
i think its asa or sas
OpenStudy (thehollywoodstud):
but i wanna say 100% its ASA
OpenStudy (anonymous):
yes u are correct
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OpenStudy (thehollywoodstud):
OK how about this one
OpenStudy (anonymous):
what do u think
OpenStudy (thehollywoodstud):
im not sure I'm correcting these problems since i got them wrong
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
since mo bisect pmn what do you think mo looks like to u
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OpenStudy (thehollywoodstud):
umm a line
OpenStudy (anonymous):
yes what is the name of that line
OpenStudy (thehollywoodstud):
line mo
OpenStudy (anonymous):
okay what is a midsegment
OpenStudy (thehollywoodstud):
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
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OpenStudy (thehollywoodstud):
thats what i have written down
OpenStudy (anonymous):
it is correct then
OpenStudy (thehollywoodstud):
ok
OpenStudy (anonymous):
just write down definition of a mid segment
OpenStudy (thehollywoodstud):
so does it go like this ?
1.given
2.definiton of angle bisector
3.reflexive property
4.given
5.definition of angle bisector
6.asa
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OpenStudy (thehollywoodstud):
can you tell me where i went wrong the first time ?
OpenStudy (anonymous):
you are correct
OpenStudy (thehollywoodstud):
all those are right ?
OpenStudy (thehollywoodstud):
@Daniel56k
OpenStudy (thehollywoodstud):
ok how about this one?
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OpenStudy (anonymous):
what do u think
OpenStudy (thehollywoodstud):
5 is asa? but i know its wrong since I'm trying to fix this one
OpenStudy (anonymous):
okay 4. is AAS
OpenStudy (anonymous):
5. D is the midpoint
OpenStudy (anonymous):
is that all
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OpenStudy (thehollywoodstud):
no how about this one ?
OpenStudy (anonymous):
what do u think
OpenStudy (thehollywoodstud):
43.25
OpenStudy (thehollywoodstud):
@Daniel56k
OpenStudy (anonymous):
That is correct
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OpenStudy (thehollywoodstud):
THIS ONE
OpenStudy (thehollywoodstud):
I got this one wrong so i have no clue
OpenStudy (anonymous):
okay state the HL theorem
OpenStudy (thehollywoodstud):
'if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.'
OpenStudy (anonymous):
okay what line is your hypotenuse
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OpenStudy (thehollywoodstud):
sr and sp
OpenStudy (anonymous):
then that is your answer
OpenStudy (thehollywoodstud):
is that right?
OpenStudy (anonymous):
yes
OpenStudy (thehollywoodstud):
ok this one @Daniel56k
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OpenStudy (anonymous):
you are asked to write out a proof what do u think
OpenStudy (thehollywoodstud):
np=om and mn=po by SSS
OpenStudy (thehollywoodstud):
@Daniel56k
OpenStudy (anonymous):
that is correct
OpenStudy (thehollywoodstud):
i have a few more
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OpenStudy (anonymous):
what do u think
OpenStudy (thehollywoodstud):
i have no clue on this one
OpenStudy (thehollywoodstud):
@Daniel56k
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
write down your given statement
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OpenStudy (anonymous):
then write out how BCA and DCE are congruent to each other
OpenStudy (anonymous):
is it SSS or AAA or SAS
OpenStudy (thehollywoodstud):
bc is congruent to ec since given
ac is congruent to dc since given
<bca is congruent to <ecd since vertical angles
^bca is congruent to ^ecd by SAS
OpenStudy (anonymous):
What about what u are asked to proof
OpenStudy (thehollywoodstud):
IM NOT SURE @Daniel56k
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OpenStudy (anonymous):
but what do u think it should be just give a guess
OpenStudy (thehollywoodstud):
asa ?
OpenStudy (anonymous):
okay if you are to prove a statement like that
Note: It is either congruent Lines like that or angles
Corresponding part of a congruent triangle are congruent
OpenStudy (anonymous):
is that all
OpenStudy (anonymous):
bc is congruent to ec since given
ac is congruent to dc since given
<bca is congruent to <ecd since vertical angles
^bca is congruent to ^ecd by SAS
Corresponding part of a congruent triangle are congruent
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OpenStudy (thehollywoodstud):
check 3 more and i should be good
OpenStudy (thehollywoodstud):
is that one right ?
OpenStudy (anonymous):
Yes
OpenStudy (thehollywoodstud):
ok how about this one ?
OpenStudy (anonymous):
correct
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OpenStudy (thehollywoodstud):
ok this one
OpenStudy (anonymous):
what do you think
OpenStudy (thehollywoodstud):
i have 100% no clue on this one
OpenStudy (anonymous):
don't be confused about what is on there
OpenStudy (thehollywoodstud):
SAS? I know it involves that
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OpenStudy (anonymous):
no
OpenStudy (thehollywoodstud):
3 times the distance from each base to get from first to home and home to 3rd would be 1/4th of the whole distance around?
OpenStudy (anonymous):
AB is congruent to CB
what do u think about this one
OpenStudy (thehollywoodstud):
huh
OpenStudy (anonymous):
what do u think it is if AB is congruent to CB
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