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Mathematics 19 Online
OpenStudy (thehollywoodstud):

need help with geometry will Fan AND MEDAL

OpenStudy (thehollywoodstud):

OpenStudy (thehollywoodstud):

THE FIRST ONE IS NQ

jhonyy9 (jhonyy9):

so than there is triangle RST similar triangle NPQ so these mean that side RS similar side NP --------------------ST ---------- PQ --------------------RT ---------- ?

OpenStudy (thehollywoodstud):

#2 is 10?

OpenStudy (thehollywoodstud):

nq??

OpenStudy (thehollywoodstud):

ok sweet can u help me with #2

jhonyy9 (jhonyy9):

for second 10 is right sure

OpenStudy (thehollywoodstud):

its ok

OpenStudy (thehollywoodstud):

can i get help with some more?

OpenStudy (thehollywoodstud):

10?

OpenStudy (thehollywoodstud):

ok can u help me with this one

OpenStudy (thehollywoodstud):

can u help me @jhonyy9

OpenStudy (thehollywoodstud):

i think its asa or sas

OpenStudy (thehollywoodstud):

but i wanna say 100% its ASA

OpenStudy (anonymous):

yes u are correct

OpenStudy (thehollywoodstud):

OK how about this one

OpenStudy (anonymous):

what do u think

OpenStudy (thehollywoodstud):

im not sure I'm correcting these problems since i got them wrong

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

since mo bisect pmn what do you think mo looks like to u

OpenStudy (thehollywoodstud):

umm a line

OpenStudy (anonymous):

yes what is the name of that line

OpenStudy (thehollywoodstud):

line mo

OpenStudy (anonymous):

okay what is a midsegment

OpenStudy (thehollywoodstud):

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.

OpenStudy (thehollywoodstud):

thats what i have written down

OpenStudy (anonymous):

it is correct then

OpenStudy (thehollywoodstud):

ok

OpenStudy (anonymous):

just write down definition of a mid segment

OpenStudy (thehollywoodstud):

so does it go like this ? 1.given 2.definiton of angle bisector 3.reflexive property 4.given 5.definition of angle bisector 6.asa

OpenStudy (thehollywoodstud):

can you tell me where i went wrong the first time ?

OpenStudy (anonymous):

you are correct

OpenStudy (thehollywoodstud):

all those are right ?

OpenStudy (thehollywoodstud):

@Daniel56k

OpenStudy (thehollywoodstud):

ok how about this one?

OpenStudy (anonymous):

what do u think

OpenStudy (thehollywoodstud):

5 is asa? but i know its wrong since I'm trying to fix this one

OpenStudy (anonymous):

okay 4. is AAS

OpenStudy (anonymous):

5. D is the midpoint

OpenStudy (anonymous):

is that all

OpenStudy (thehollywoodstud):

no how about this one ?

OpenStudy (anonymous):

what do u think

OpenStudy (thehollywoodstud):

43.25

OpenStudy (thehollywoodstud):

@Daniel56k

OpenStudy (anonymous):

That is correct

OpenStudy (thehollywoodstud):

THIS ONE

OpenStudy (thehollywoodstud):

I got this one wrong so i have no clue

OpenStudy (anonymous):

okay state the HL theorem

OpenStudy (thehollywoodstud):

'if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.'

OpenStudy (anonymous):

okay what line is your hypotenuse

OpenStudy (thehollywoodstud):

sr and sp

OpenStudy (anonymous):

then that is your answer

OpenStudy (thehollywoodstud):

is that right?

OpenStudy (anonymous):

yes

OpenStudy (thehollywoodstud):

ok this one @Daniel56k

OpenStudy (anonymous):

you are asked to write out a proof what do u think

OpenStudy (thehollywoodstud):

np=om and mn=po by SSS

OpenStudy (thehollywoodstud):

@Daniel56k

OpenStudy (anonymous):

that is correct

OpenStudy (thehollywoodstud):

i have a few more

OpenStudy (anonymous):

what do u think

OpenStudy (thehollywoodstud):

i have no clue on this one

OpenStudy (thehollywoodstud):

@Daniel56k

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

write down your given statement

OpenStudy (anonymous):

then write out how BCA and DCE are congruent to each other

OpenStudy (anonymous):

is it SSS or AAA or SAS

OpenStudy (thehollywoodstud):

bc is congruent to ec since given ac is congruent to dc since given <bca is congruent to <ecd since vertical angles ^bca is congruent to ^ecd by SAS

OpenStudy (anonymous):

What about what u are asked to proof

OpenStudy (thehollywoodstud):

IM NOT SURE @Daniel56k

OpenStudy (anonymous):

but what do u think it should be just give a guess

OpenStudy (thehollywoodstud):

asa ?

OpenStudy (anonymous):

okay if you are to prove a statement like that Note: It is either congruent Lines like that or angles Corresponding part of a congruent triangle are congruent

OpenStudy (anonymous):

is that all

OpenStudy (anonymous):

bc is congruent to ec since given ac is congruent to dc since given <bca is congruent to <ecd since vertical angles ^bca is congruent to ^ecd by SAS Corresponding part of a congruent triangle are congruent

OpenStudy (thehollywoodstud):

check 3 more and i should be good

OpenStudy (thehollywoodstud):

is that one right ?

OpenStudy (anonymous):

Yes

OpenStudy (thehollywoodstud):

ok how about this one ?

OpenStudy (anonymous):

correct

OpenStudy (thehollywoodstud):

ok this one

OpenStudy (anonymous):

what do you think

OpenStudy (thehollywoodstud):

i have 100% no clue on this one

OpenStudy (anonymous):

don't be confused about what is on there

OpenStudy (thehollywoodstud):

SAS? I know it involves that

OpenStudy (anonymous):

no

OpenStudy (thehollywoodstud):

3 times the distance from each base to get from first to home and home to 3rd would be 1/4th of the whole distance around?

OpenStudy (anonymous):

AB is congruent to CB what do u think about this one

OpenStudy (thehollywoodstud):

huh

OpenStudy (anonymous):

what do u think it is if AB is congruent to CB

OpenStudy (thehollywoodstud):

I'm really confused

OpenStudy (anonymous):

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