he table below shows the distance d(t) in meters that an object travels in t seconds: t (seconds) d(t) (meters) 3 126 4 224 5 350 6 504 What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent?
the table below shows the distance d(t) in meters that an object travels in t seconds: t (seconds) d(t) (meters) 3 126 4 224 5 350 6 504 What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent? 59.5 m/s; it represents the average speed of the object between 3 seconds and 5 seconds 112 m/s; it represents the average speed of the object between 3 seconds and 5 seconds 112 m/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds 59.5 m/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds
\[\frac{ \Delta d }{ \Delta t } = \frac{ 350 - 126 }{ 5-3 } = \] The average change represents the constant average linear speed at this interval.
224/8
@TrojanPoem
112
5 - 3 is 2 not 8
ok
so a or b
i mean b or c
i think its b am i right @TrojanPoem
Yeah.
Thanks
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