Question

Is this correct?!?


The probability that a bus leaves on schedule is 0.92. The probability that a bus leaves and arrives on schedule is 0.87.
A.) What is the probability that the bus arrives on schedule, given that it leaves on schedule?
B.) What does this mean in the context of the situation?

A: Let A = leaves on schedule and
B = arrives on schedule
P(A) = 0.92 and P(A∩B) = 0.87
P(B | A) = P(A∩B) over P(A) = $0.87/0.92$ ≈ 0.946 or 94.6%

B: Recall that P(B | A) symbolizes the probability that event B will happen if it is certain that event A has happened...

Answer 1

In this scenario, P(B | A)≈ 94.6% means that if the bus leaves on schedule (event A), then there is a 94.6% chance that it will also arrive on schedule (event B).

Answer 2

yes thats correct

Answer 3

seems correct. ima bad at probability

Answer 4

its right

Answer 5

Yeah, looks correct. I'm also bad at probability, but I recall the steps, and you got it quite right. Good job.

Answer 6

Thanks guys :D