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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
i bet it is \[\frac{2}{3}(x-2)=4x\] am i right?
OpenStudy (lina17):
\[\frac{ 2 }{ 3}(x-2)=4x\]
OpenStudy (misty1212):
yeah that is what i thought
i would get rid of the annoying fractions right away and multiply both sides by \(\frac{3}{2}\)
OpenStudy (misty1212):
that will leave you with just \(x-2\) on the left
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OpenStudy (misty1212):
what is \[\frac{3}{2}\times 4x\]?
OpenStudy (lina17):
would it be \[\frac{ 16 }{ 8}\]
OpenStudy (misty1212):
no
OpenStudy (misty1212):
\[\frac{3}{2}\times 4\]
divide 4 by 2, then multiply the result by 3
OpenStudy (lina17):
so would it be 9
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OpenStudy (misty1212):
no not 9
lets go slow
what is 4 divided by 2?
OpenStudy (lina17):
2
OpenStudy (misty1212):
ok and what is \(3\times 2\)?
OpenStudy (lina17):
6
OpenStudy (misty1212):
ok good
that makes \[\frac{3}{2}\times 4x=6x\]
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OpenStudy (lina17):
ok
OpenStudy (misty1212):
so now finally we have \[x-2=6x\] you need to solve that one
OpenStudy (lina17):
5x
OpenStudy (misty1212):
yes you get \[-2=5x\]
OpenStudy (lina17):
so would it be \[-\frac{ 2 }{ 5 }\]
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OpenStudy (misty1212):
yes it would
OpenStudy (lina17):
thanks so much
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
jhonyy9 (jhonyy9):
2
----(x−2)=4x
3
- so i think one more easy way to solve same exercise
2 4x
----(x-2) = ---- in this case cross multiplie and will get
3 1
1*2(x-2) = 3*4x
2(x-2) = 12x
2x-4= 12x
2x-2x-4 = 12x-2x
-4 = 10x divide both sides by 10
-4/10 = x
-2*2/(2*5) = x so simplifie by 2
-2/5 = x