Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four sides are equal.

Question

anonymous · Answer

A.	BD = CE = square root of 50
	B.	BD = CE = 50
	C.	BC = CD = DE = EB = 50
	D.	BC = CD = DE = EB = square root of 50

anonymous · Answer

@peachpi

anonymous · Answer

Use the distance formula to find the length of each side.
$$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$

anonymous · Answer

for a rhombus all four side have to be equal, so it's has to be c or d

anonymous · Answer

Ok. I think C am I correct, or do you not know the answer?

anonymous · Answer

I know, but you actually have to put two of the points into the formula. You won't get 50 when you do that

anonymous · Answer

Oh ok I get it now it is D

anonymous · Answer

yes