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Mathematics 11 Online
OpenStudy (anonymous):

Please do questions attached Medal+Fan

OpenStudy (anonymous):

OpenStudy (anonymous):

questions attached to this message

OpenStudy (mathstudent55):

In general, the probability of an event happening is the number of desired outcomes divided by the total number of outcomes. In problems 1 through 6, each probability is the number of tickets of that event divided by the total number of tickets

OpenStudy (anonymous):

can u give me an example of how to solve number 1

OpenStudy (mathstudent55):

1. You are interested in the probability of drawing a basketball ticket. You need to know how many basketball tickets there are (the desired event) and the total number of tickets (the total number of outcomes). Then divide. \(p(basketball) = \dfrac{number~of~basketball~tickets}{total~number~of~tickets} \)

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