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OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
@satellite73
OpenStudy (anonymous):
the sum of the exponents of the first term is \(1+2=3\)
OpenStudy (anonymous):
The order of a polynomial is the higher power in your variable, in your case you have two variables "x" and "y", the higher power of y is 2 and 1 for x, so this polynomial is second order in y and first order in x
OpenStudy (anonymous):
that is how you find the degree
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OpenStudy (anonymous):
so the sum of them is 3
OpenStudy (rootbeer003):
d?
OpenStudy (anonymous):
what @M4thM1nd said
OpenStudy (anonymous):
yeah 3 ... er D
OpenStudy (rootbeer003):
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OpenStudy (rootbeer003):
my brain hurt when i did this
OpenStudy (anonymous):
when the question asks you to arrange, it means to write the polynomial in decreasing order, so the last answer is correct
OpenStudy (anonymous):
just list from the highest degree (exponent) to the lowest
OpenStudy (rootbeer003):
so was i right?
OpenStudy (anonymous):
yes
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OpenStudy (rootbeer003):
yeeesshhhhh
OpenStudy (anonymous):
even a stopped clock is right twice a day
you are always right
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
idk bout this one
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
correct
OpenStudy (rootbeer003):
oo woott
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
ok but this one is idk
OpenStudy (anonymous):
also correct
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OpenStudy (anonymous):
yes
OpenStudy (rootbeer003):
man
OpenStudy (anonymous):
on a roll
OpenStudy (rootbeer003):
yes ik
OpenStudy (anonymous):
good practice for when you teach math in a few years
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OpenStudy (rootbeer003):
hahahahahahaha thats funny
OpenStudy (anonymous):
keep going like that!
OpenStudy (rootbeer003):
ill teach 1sst grade
OpenStudy (rootbeer003):
ok i have a few idk
OpenStudy (rootbeer003):
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OpenStudy (anonymous):
we did a bunch like these
what is the problem with adding exponents?
OpenStudy (rootbeer003):
bruhhh
OpenStudy (anonymous):
Just sum the exponents of the same variable
OpenStudy (rootbeer003):
b?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
\[\huge x^2\times x^3=x^{2+3}=x^5\]
OpenStudy (rootbeer003):
its b yes?
OpenStudy (anonymous):
oui
OpenStudy (anonymous):
yup
OpenStudy (rootbeer003):
satellite
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OpenStudy (rootbeer003):
do you expect me to know what that means
OpenStudy (anonymous):
oui
OpenStudy (rootbeer003):
when i dont even know how to add
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
oiii
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OpenStudy (anonymous):
multiply each number by 10, add 1 to each exponent
OpenStudy (rootbeer003):
a?
OpenStudy (anonymous):
no, you have to add one to each exponent
OpenStudy (rootbeer003):
b
OpenStudy (anonymous):
yes
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OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
um d?
OpenStudy (anonymous):
they all have \(6x^2\) and \(12\)
OpenStudy (rootbeer003):
when ever you take long typing ik im wrong
OpenStudy (anonymous):
so the question is, what is
\(4\times 2x+3\times 3x\)?
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OpenStudy (anonymous):
oh i didn't even look at D yet
lets see
OpenStudy (rootbeer003):
12!
OpenStudy (anonymous):
really?
OpenStudy (rootbeer003):
C:
OpenStudy (anonymous):
\[4\times 2+3\times 3=?\]
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OpenStudy (rootbeer003):
17
OpenStudy (anonymous):
yeah so i hope one answer is \[6x^2+17x+12\]
OpenStudy (rootbeer003):
im always right
OpenStudy (anonymous):
except when it comes to arithmetic
OpenStudy (rootbeer003):
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OpenStudy (anonymous):
"tri" = 3
OpenStudy (rootbeer003):
a?
OpenStudy (anonymous):
yes
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
d?
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OpenStudy (anonymous):
no \[5x+2x+4x=?\]
OpenStudy (rootbeer003):
11
OpenStudy (anonymous):
OH OOPS
OpenStudy (anonymous):
i means "yes"
OpenStudy (rootbeer003):
OHHH I WAS RIGHTTTTTTT
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OpenStudy (rootbeer003):
BOOOOOOOOOOOOOOOOOOM
OpenStudy (anonymous):
yeah yeah you are always right ...
OpenStudy (rootbeer003):
OpenStudy (rootbeer003):
um idk d?
OpenStudy (rootbeer003):
wait no
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OpenStudy (anonymous):
um no
really no this time
OpenStudy (rootbeer003):
its c?
OpenStudy (anonymous):
yes it is
OpenStudy (rootbeer003):
omg i feel smart
OpenStudy (anonymous):
\[(x-4)(x-4)=x^2-4x-4x+16=x^2-8x+16\]
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