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solve using u-substitution? @michele_laino
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here, we can make this variable change: \(\large 3+e^x=u\)
du/dx would equal e^x right?
yes!
k, so it would simplify to |dw:1453502398187:dw| right?
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correct! Nevertheless better if we don't write the limits of integration at this step
okay, and then that's \(\large \ln|3+e^x|\)
right?
and then solve for the interval?
correct! since the function \(3+e^x\) is always positive, we can eliminate the symbol of absolute value
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okay
I got approx 0.954
yes! We can do this computation: \[\Large \ln \left( {3 + {e^2}} \right) - \ln \left( {3 + 1} \right) = ...?\]
Thank you for the help!
:)
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