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An angle in standard position measures 5π/6 radians and intercepts a circle with center at (0,0) and radius 4. Find the length of the arc determined by the points of intersection. HELP PLEASE :(
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So how much around a circle is 5pi/6?
well let's see
5/6 of a \(\pi\) that is |dw:1453505154615:dw| so, we know the angle, "in radians" we also know the radius of the circle it intercepts so, how long is the "arc"? well \(\large \textit{arc's length}=s=r\theta\qquad \begin{cases} r=radius\\ \theta=\textit{angle in radians} \end{cases} \)
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