Question

Solve each system of equations by using elimination.
3p+9q=6
5p-5q=30

Answer 1

Think about eliminating the -5q with the 9q
How are you going to do it ?

Answer 2

Im not sure how to solve that, im used to it with opposites there already. for example if it was a 9q and a -9q i could solve it

Answer 3

Yes
So you have to Multiply one of the two equations by a number which could make the -9q and of course you will muliply the one which contains the -5q

Answer 4

but, how are we going to get this number

Answer 5

AM i multiplying it by -1

Answer 6

No
you have to look for a factor which relates the -5 and the -9
in other words which number will convert the -5 to -9

Answer 7

1.8

Answer 8

yes
So do it

Answer 9

I got 3p + 9q=6 and 9p-9q=54. Is this right?

Answer 10

After doing it you should have the two equations:
\[3p+9q=6\]
9p-9q =54

Answer 11

Exactly

Answer 12

Now Add the two equations

Answer 13

i got p = 5

Answer 14

You notice that -9q and 9q is the same number but different signs,so upon adding they will be eliminated together

Answer 15

Exactly, Great Job.well Done
this is the adding by eliminating

Answer 16

ANd i plug the 5 in right?

Answer 17

so you know that 5p-5q = 30 and again that p=5 than substitute the 5 in place of p and calculi the value of q

ok. ?