Question

Please help me Algebra 2

Answer 1

Solve each equation.

8x2 - 24 = 3x2 - 9

Answer 2

put it first in this form
ax^2 + bx + c = 0

Answer 3

i dont even get this at all

Answer 4

just move parts around to get it into the standard quadratic form a*x^2 + b*x + c = 0

8x^2 - 3x^2 - 24 + 9 = 0

5x^2 - 15 = 0

Answer 5

ok i have to find what x equals

Answer 6

yes, you can always use the quadratic formula to find that , do you remember this thing

\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 7

this is the first time ive ever done this lol i have no clue what im doing

Answer 8

an equation in form

a*x^2 + b*x + c = 0

has solutions

\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \]

Answer 9

you have 5x^2 - 15 = 0

a *x^2 + b*x + c = 0
5 *x^2 + 0*x + (-15) = 0

you can put in those values for a,b,c

a=5, b=0, c=-15

Answer 10

ok that part makes since

Answer 11

there no examples in your book or notes to follow and practice?

Answer 12

no

Answer 13

here are a few, all those equations are the same form, quadratic

ax^2 + bx + c = 0

solving using factoring, or the quadratic formula like we using here

Answer 14

that just makes it a little more confusing for me