Question

how many liters (L) of pure water should be mixed with a 5-L solution of 60% acid to produce a mixture that is 50% water?

Answer 1

can I help

Answer 2

Yes

Answer 3

I am here

Answer 4

how much present an% do you think

Answer 5

@Jones2015Calvin

Answer 6

It's asking how many liters

Answer 7

I know

Answer 8

What are you asking me?

Answer 9

common

Answer 10

how much present you know the answer

Answer 11

means what do you think the answere is

Answer 12

Would it be set up as 0x+.6(5)= .5(5+x)

Answer 13

noooooooooo

Answer 14

Then I don't know the answer

Answer 15

I under stand that's why I am here for

Answer 16

So how should it be set up ?

Answer 17

5 L of 60% acid =3 L of acid 2 L of water


How much water to add to make it 50% water?
concentration = acid volume / total volume
.6 = 3L / 5L
We need .50 Concentration so
.5 = 3L / Total Volume
Total Volume = 3L / .5

Total Volume is 6 L so we must add 1 liter of water

Answer 18

10

Answer 19

Why do you say 10?

Answer 20

Difference between.5 and.6

Answer 21

I'm pretty sure it is 1 liter.
Did you look at my answer?

Answer 22

I see it now

Answer 23

So, I'm right?

Answer 24

Yes now it's asking how many Liters of pure water should be mixed with a 6-L solution of 90% acid to produce a mixture that 40% water

Answer 25

6L of 90% acid
How much water to add to make it 40% water?

6L .90 acid = 5.4 L acid .6 L water
We need 40% water so
concentration = acid volume / total volume
.4 = 5.4 L / total volume
total volume = 5.4L / .4
total volume = 13.5 L
So, we have to add 13.5 - 6L = 7.5 L water

Answer 26

Where the 5.4 come from

Answer 27

The original solution is 6 L of 90% acid
So,
original solution = 90% acid 10% water
acid volume = .9 * 6 = 5.4 Liters
water volume = .1 * 6 = .6 liters

Answer 28

What's next

Answer 29

.

Answer 30

Can you give me a better understanding

Answer 31

From the view of acid it is
since 100% water has 0% acid
0*x+.6*8=0.5(8+x)
4.8=4+.5x
.8=.5x
.8/.5=x
x=1.6 L
view of water
I changed from percent acid to percent non acid
60% acid means 40 % non acid
50% acid means 50 % non acid

Answer 32

@Jones2015Calvin

Answer 33

Would that work for how many Liters of pure water should be mixed with a 6-L solution of 90% acid to produce a mixture that 40% water

Answer 34

Pure water is 100% non acid as a decimal 100%=1
1*x+0.4*8=0.5(8+x)
1*x+3.2=4+0.5x
1x-0.5x=4-3.2
0.5x=0.8
x=1.6 L Same answer!!!!
check
1*1.6+0.4*8=0.5(8+1.6)
1.6+3.2=0.5(9.6)
4.8=4.8
ok

Answer 35

Oh your Equation:
water + water = water
1*x + 0.40*8 = 0.50(x+8)

Answer 36

@Jones2015Calvin Is that another question?

Answer 37

I guess Jones2015Calvin isn't here anymore.
I'm surprised h still remained. I left here about an hour ago.

Answer 38

oh lol

Answer 39

Yes I'm here