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Mathematics 18 Online
OpenStudy (thecalchater):

The fundamental theorem of Calculus. Help?

OpenStudy (thecalchater):

@zepdrix @phi @dan815

zepdrix (zepdrix):

Ooo the 4th one is pretty fun :)

OpenStudy (caozeyuan):

ok, so you want to integrate y over the interval, can you write the experssion

OpenStudy (thecalchater):

Is my 1st one right?

OpenStudy (caozeyuan):

yes

OpenStudy (thecalchater):

For number 2 I got 1/3 is that right too?

zepdrix (zepdrix):

yes c:

OpenStudy (thecalchater):

ok so number 3 and 4 I am confused

OpenStudy (thecalchater):

I know for 4 they are looking for the inverse but how do i get it?

zepdrix (zepdrix):

Inverse? :o Derivative silly! :)

OpenStudy (thecalchater):

ohhhhhhh my bad nvm give me a second

zepdrix (zepdrix):

You have to apply the Fundamental Theorem of Calculus, Part 1:\[\large\rm \frac{d}{dx}\int\limits_c^x g(t)dt=g(x)\] Actually it might be useful to use BOTH parts of the theorem for this problem.

OpenStudy (thecalchater):

I got 18x^3 for the derivative of it.

OpenStudy (thecalchater):

but that isnt a choice =C

OpenStudy (thecalchater):

For nuber 3 I got B. and number 4 I don't know.

OpenStudy (thecalchater):

I got 18x^3 when I integrated but 0 for the derivative...**

OpenStudy (caozeyuan):

for 4 you have to experss F as a function of x, not as intergration

OpenStudy (thecalchater):

I got 18x^3 when i integrated bu 0 as the derivative**

zepdrix (zepdrix):

This is what we're trying to figure out problem 4,\[\large\rm \frac{d}{dx}\int\limits_{-3x}^{3x}s^2ds\]Try to think of it more generally like this,\[\large\rm \frac{d}{dx}\int\limits_{-3x}^{3x}f(s)ds\]You anti-differentiate to get some function, let's call it F(s)

zepdrix (zepdrix):

\[\large\rm \frac{d}{dx}\int\limits\limits_{-3x}^{3x}f(s)ds\quad=\frac{d}{dx}F(s)|_{-3x}^{3x}\]

zepdrix (zepdrix):

Plug in your limits,\[\large\rm \frac{d}{dx}\left[F(3x)-F(-3x)\right]\]and now take a derivative

zepdrix (zepdrix):

Big F turns back into the original function, little f, but we have some chain rule going on, right?\[\large\rm =3f(3x)--3f(-3x)\]

OpenStudy (thecalchater):

yeah

zepdrix (zepdrix):

little f is the thing we started with, s^2 in this case, So now we have the 3x and -3x being squared, replacing the s value,\[\large\rm =3(3x)^2+3(-3x)^2\]And simplify! :)

zepdrix (zepdrix):

It's a weird little trick. If you got confused somewhere in that process, I wouldn't be surprised.

OpenStudy (thecalchater):

54x^2 so c. Now number 3.

OpenStudy (thecalchater):

so b*

OpenStudy (thecalchater):

I'm going to close this one and open a new one

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