medal to anyone that helps Match each system of linear equations with the quadrant in which the solution lies. 3x + 2y = 14 x - 3y = -10 2x + 3y = -12 4x - 2y = -2 3x - 2y = 10 5x + 3y = 4 x + 2y = 8 4x + 6y =22
anyone there
Hi there!
can you help me
For these I would solve for x or y than do substitution for the variable you solved or, you could also do the elimination method, getting the x or y's to cancel and and than getting an answer for x or y and plugging that back in into one of those variables to find the other one
I can explain both ways for you on any number you want
can you help with all them plz
Sure, i'll do substitution for 2 and elimination for 2 if thats okay so you know two ways, elimination is my favorite personally
you will do all them in two ways
3x+2y=14 x-3y=-10 Would you like to figure out x or y? Me personally I would do x for the bottom because all you have to do is add 3y to both sides, but its your choice
I just want to get the question thx tho
Thats how you have to do it though, otherwise it will take way to long to try and find the coordinates that work for both equations
Unless you get lucky
ok thx this is all new to me
Have you learned the substitution or elimination method?
You would have to cancel one of the variables for elimination its much easier than substitution and takes way less time
I think but when you solve the problems I understand
Okay, if you wanna try number one if you think you can let me know what you get and I'll tell you what I get if you don't know where to start i'll help
I don't know how to do this its why I put it in this site
Okay so 3x+2y=14 X-3y=-10 So you would have to mutiple the bottom by -3 the whole function, because than the x's would cancel so you would have 2y=14 on the top on and -3(-3y)=-3(-10) So than you will have 2y=14 on the top and 9y=30 and you add those values so you will have 11y=44 than divide by 11 so y=4 and than plug 4 in for 4 so 3x+2(4)=14 so than 3x+8=14 subtract 8 3x=6 x=2 so your coordinate is (2, 4) so the coordinate is in the first quadrant
Making use of Kayder's suggestion, and multiplying the 2nd equation by -1, we get first equation: 3x + 2y = 14 -3x+ 9y = 30 ------------- Please add these two equations together, column by column. What's left? ( ? ) y = ( ? )
thx are you guy and girl going to help with the others? plz
I'd be glad to help after you've started each problem and gone as far as you can before getting stuck. At that point, ask questions!
Same, I wanna be a math teacher so I would love to help you
i want to help you pup02
ok you all can help I just don't get this sorry
If it was on paper would that help more?
idk
iam sorry , iam not very good in english so, please tell me what do you want exactly for the previous equations
You camt add pictures shoot
what are the other three
Do you still need help on the first part?
Where you have to multiply
To eliminate a variable
I got the first one I just need you to do the other three problems
2x+3y=-12 4x-2y=-2 what would you have to multiply to the top to get opposites for x's
Opposites signs, but same number so basically get -4x
you want to know what are x and y equal at all the three equations?
what quadrant the solution is in
so it would be in the third quadrant
yes i understand
That depends on what you get for x and y if you get positive for both you get quadrant 1 if x is negitive and y positive than its quad 2 if they are both negitive than quad 3 if y is negitive and x is positive than y is negitive than it is quad 4
But you first have to do that elimination method
so pup let me solve it for you . to know which quadrant we must get the values of x and y so in the first problem x=3.2 and y=4.4 so it will be at quadrant 1
that is for the first quastion
yes
No
Plug it back i to both equtions you dont get those answers
for the equations 3x+y=14 x-3y=-10
ok what are the other three
The answer is x=2 y=4
ok what is the answer for the second answer.
yes you are right because i have seen the first equation 3x+y=14
so the answers are for the first problem x=2 y=4 an the quadrant 1 for the second problem x=-15/8 y=-11/4 and the quardant is 3
ok that's really is great thanks for helping me
what is the third question
if you want any help contact me anytime
the third is x=2 y=-2 in the quadrant 4
thank you
2x + 3y = -12 4x - 2y = -2 Okay for this equation you would multiply the top by -2 so than -2(2x+3y equal -12) so than you will have -4x+-6y=24 and the bottom equation would stay the same so now you add -4x+4x=0 And -6y +-2y =-8y and 24+-2=22 so than -8y=22 so than it will be 22/-8 which can be reduced to -11/4 and than plug that into y and than it will be 2x=+3(-11/4) =-12 so 2x-33/4=-12 so add 33/4 so 2x=2x=-15/4 than divide by 2 so x=-15/8 so both x and y are negitive so than you will be in quadrant 4
quadrant 3 my bad
haha thank you all
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