Will someone please explain this to me? And help me I REALLY don't understand what I'm doing Evaluate each expression for the given values. Provide answers in simplified radical form and approximate irrational answers to the nearest hundredth.
\[15+2\sqrt{a+8} -\sqrt{3a}\] when a=4
\[2\sqrt{(x+y)-(x-y)^{2}}\] when x=8 and y=5
\[3\sqrt{(ab)^{2}}+(2a+b)^{3}\] when a =1 and b=4
\[15+2\sqrt{a+8} -\sqrt{3a}\] for \(a=4\) start with \[15+2\sqrt{4+8} -\sqrt{3\times 4}\]
there is more work to be done, but what do you get first?
\[17\sqrt{12}-\sqrt{12}\]
hmm no
you can't add them like that, the first step is \[15+2\sqrt{12}-\sqrt{12}\]
sort of like \[15+2x-x\] what do you get when you combine like terms there?
15+2x-x 2x
where did the 15 go?
15+2x
ok that is somewhat better but still not right what is \[2\times 5-5\]?
\[2\times5=10-5=5\]
right and how about \[2\times 7-7\]?
\[2\times7=14-7=7\]
ok good, so \[2\times 5-5=5\\2\times 7-7=7\\ 2\times x-x=?\]
5 and 7 would be the two x's?
yes just trying to make sense out of \(2x-x\) for example \(x\) could be an apple two apples minus one apple is ?
if we had 2-1=1
yes but is it not the number 2-1= 1 it is two apples minus one apple equals one apple \[2\spadesuit -\spadesuit=\spadesuit\] \[2x-x=?\]
the problem already gives us 2 \[2(2)-1=3?\] is that how we would set it up and solve?
no, we are still at \[15+2\sqrt{12}-\sqrt{12}\]
now the first question is, what is \(2\sqrt{12}-\sqrt{12}\)?
the factors of \[\sqrt{12}\] would be \[\sqrt{3} and \sqrt{4}\]and 4 can go smaller \[\sqrt{2}\]
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