Question

--=Correct My Answers?=Just One!

Answer 1

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective function.
x>0
y>0
y<1/3x+3
5>y+x
Objective Function: C = 6x – 4y

Answer 2

My answer: Min is C = -12 which occurs at (0,3)


Max is C = 30 which occurs at (5,0)

Answer 3

@inkyvoyd --Correct My Answer?---

Answer 4

@Awolflover1 --Correct My Answer?---

Answer 5

@sweetburger --Correct My Answer?---

Answer 6

@bahrom7893 --Correct My Answer?---

Answer 7

@satellite73 --Correct My Answer?---

Answer 8

@zepdrix --Correct My Answer?---

Answer 9

@xapproachesinfinity --Correct My Answer?---

Answer 10

@pooja195 --Correct My Answer?---

Answer 11

@Luigi0210 --Correct My Answer?---

Answer 12

@Lollygirl217 : for anyone to check your answer would require that that person go through the entire problem and reach his or her own solution.
That's asking a lot.
I'd bet you'd get more responses if you share your actual graph, thus sparing others the labor of constructing one.
I'd also suggest you move on, rather than trying so hard to ensure that your current problem solution is 100% correct.

Answer 13

@mathmale Yes. Right. I shall post how I got the answer.

Answer 14

Plug in (x,y) = (0,0)


C = 6x - 4y


C = 6(0) - 4(0)


C = 0


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Plug in (x,y) = (0,3)


C = 6x - 4y


C = 6(0) - 4(3)


C = -12


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Plug in (x,y) = (5,0)


C = 6x - 4y


C = 6(5) - 4(0)


C = 30


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Plug in (x,y) = (1.5,3.5)


C = 6x - 4y


C = 6(1.5) - 4(3.5)


C = -5


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Summary:


Min is C = -12 which occurs at (0,3)


Max is C = 30 which occurs at (5,0)

Answer 15

8) substitute/eliminate x = +y +3/2z-0
substitute/eliminate y = -2/3z+1
Solution: x = 1; y = 1; z = 0; (x, y, z) = (1, 1, 0)