Am I wrong if so why and how? (high not middle clicked wrong one)
Sean want to make a mixture that is 50% lemon juice and 50% lime juice. How much 100% lemon juice should he add to a juice that is 30% lemon juice 70% lime juice to make 7 gallons of the 50%lemon/50%lime juice mixture? 0.5gallons 1gallons 2gallons 2.5 gallons
i think its 2
@Compassionate @tkhunny @nincompoop
tk what do you think?
Equate the Lemon Juice X = Starting Quantity Y = Additional Quantity 30% * X + 100% Y = 50% (X+Y) And we know X+Y = 7 Equate the Lime Juice X = Starting Quantity Y = Additional Quantity 70% * X + 0% Y = 50% (X+Y) And we know X+Y = 7
ok
I don't know. I didn't solve the either equation. Why do you believe it to be 2?
i calculated it and it came out to 2 but i believe im incorrect....
@tkhunny
can you at least tell me if im right or wrong?
@phi can you help
we have to solve a system of equations. There are two parts to doing this: 1) figure out the equations 2) solve the equations tk did step 1 now you can try to do step 2
how im totally confused
See if this makes sense: we have an unknown amount of 30% lemon/70% lime. call this amount x what fraction of that is lemon? any idea?
uhm would it be some where around 3/5?
How about with real numbers. say you had 100 gallons of 30% lemon / 70% lime any idea how many gallons of the 100 is lemon ?
no
ok, how about this different problem: you have 100 gallons of 50% lemon and 50% lime how many of the 100 gallons is lemon. any idea ?
50
so that would be 30
yes, 50 gallons. and yes 30 gallons for the first problem the "thought" is 30% of 100 means 30/100 * 100 or 0.30 * 100 (we can write 30% as either a fraction 30/100 or as a decimal 0.30) we then multiply so 10% of 20 would be 0.10*20 = 2 or 10/100 * 20 = 1/10 * 20 = 2 (or use a calculator) ok so far?
yes so now what?
now back to 30% lemon/70% lime and we have x gallons of it we use the same thought: the amount of lemon is 30% of x and we do the same thing: 0.30*x or 0.3x or 30x/100 the decimals are easier to type so 0.3x is the number of gallons of lemon juice in the 30/70 stuff.
yes
next , we add 100% lemon juice. we don't know how much that is, so we give it a name "y" we add y gallons of pure lemon juice. how much lemon juice will we have? can you take a stab at writing that down ?
in other words, we start with 0.3x of lemon juice and add y gallons
i have been
how do we show 0.3x added to y ?
0,3x+y
0.3x*
yes. next, we remember x is the number of gallons of juice (both lemon and lime) and we pour in y gallons (of lemon) how many gallons total do we have ?
30%?
no, don't think percent. just imagine you have a bucket with x gallons of juice and you pour in y more gallons how many gallons total is in the bucket ?
30
I want you to think: x+y we start with x gallons and add y more gallons
70?
no, we can't do numbers. we have to use the letters all we know (so far) is we have x+y gallons of juice but we are told 50%lemon/50%lime juice this new mixture is 50% lemon juice how much lemon juice is in the (x+y) gallons ?
50
50% of (x+y)
?
can you imagine having "x" gallons of juice and adding "y" gallons? does that make sense or is it confusing ?
x+y
and if I said that 50% of that (x+y) is lemon, how do we write that ?
50+50?
you change the 50% to a decimal and you multiply it times (x+y) can you do that ?
0.3x+y
we are now doing 0.5*(x+y) that is the amount of lemon juice in the new solution and we know 0.3x+y is also the amount of lemon juice they are equal amounts, so we write 0.3x+y= 0.5(x+y) do you know how to "distribute" the 0.5 on the right side ?
no
0.5(x+y) means multiply 0.5 times x and multiply 0.5 times y try it
ok phi i have to go thank you for every thing sorry for have to cut this short once again thank you for the help :) i have already fanned you but here is a medal
thank you!
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