Question

4.Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).
Rest of the question in comments!!

Answer 1

@aaronq

Answer 2

4. Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).
• Write a balanced equation for this reaction.
• Assuming that all volume measurements occur at the same temperature and pressure, how many liters of oxygen will be required to completely burn 0.700 L of propane gas?
• Assuming that all volume measurements occur at the same temperature and pressure, how many liters of carbon dioxide gas will be produced in the reaction?
• Assuming that all volume measurements occur at the same temperature and pressure, how many liters of water vapor will be produced in the reaction

Answer 3

@aaronq @Photon336

Answer 4

have you written an equation?

Answer 5

no i havent

Answer 6

give it a try

Answer 7

would it be C3H8 + O2 --> CO2 + H2O ?

Answer 8

yep! now balance it

Answer 9

Idk how to balance well, but I will try

Answer 10

would it be C3H8 + O2 --> C3O2 + H8O2 ?

Answer 11

no you can't change the formulas, you can only put coefficients infront of the formulas that work as multipliers, like the distributive property in math.

2(2x+y)=4x+2y

Answer 12

2 H2O = 4 H's and 2 O's

Answer 13

Oh ok

Answer 14

try again

Answer 15

C3H8 + O2 --> 3CO2 + 2H2O ?

Answer 16

close, the H's arent balanced. First balance those then balance the O's with \(O_2\) on the left.

Answer 17

C3H8 + O2 --> 3CO2 + 4H2O2

Answer 18

you changed the last formula again :P It's like this

C3H8 + 5 O2 --> 3 CO2 + 4 H2O

Answer 19

Oh ok

Answer 20

now because the conditions remain the same, we can say that moles are proportional to moles. We build a ratio of the moles (liters in this case) and the stoichiometric coefficients (we just found).

\(\sf \dfrac{O_2~liters}{O_2's~coefficient}=\dfrac{propane~liters}{propnane's ~coefficient}\)

plug stuff in and solve liters of O2

Answer 21

So what do we plug in? which numbers?

Answer 22

I wrote what you should plug in in the equation itself

Answer 23

so I know 5/2 = x/8 is that right

Answer 24

no, the question reads: "Assuming that all volume measurements occur at the same temperature and pressure, how many liters of oxygen will be required to completely burn 0.700 L of propane gas?"

try again

Answer 25

x/2 = .700/8

Answer 26

almost, the coefficients aren't right

Answer 27

x/5 = .700/3

Answer 28

the coefficient of propane is 1

Answer 29

oh ok

Answer 30

x/5 = .700/1

Answer 31

yep! that's for liters of O2

I have to get going, sorry! maybe photon can help ya

Answer 32

x = 3.5

Answer 33

oh ok, thanks

Answer 34

@Photon336 can you help me?

Answer 35

@sweetburger hey can you help?

Answer 36

I have class at 4:45. I will gladly help at around 7:30 when I'm out just let me know then if you still need help. Sorry :/