Question

Find two consecutive even integers such that four times the first equals three times the second.

Answer 1

let 2n. 2n+2 be the consecutive even integers
4(2n)=3(2n+2)

Answer 2

that is the translation of the problem

Answer 3

find n and then multiply by 2 to find to get first integer
what you get add 2 to it that gives the following integer

Answer 4

2 mulip what again

Answer 5

Two consecutive integers
The first we can call n
and to make sure it is even we double it, creating 2n
the second has to be then next one because of the word consecutive so 2(n+1)
Four times the first = 4(2n)
Three times the second = 3 · 2(n+1)
So
4(2n) = 3 · 2(n+1)
now simplify
8n = 6n + 6
subtract 6n on both sides
2n = 6
n = 3
2(3) = 6
2(3+1) = 8
So the first number was 6 and the second was 8

Answer 6

Ok how would i type that in as a answer

Answer 7

The first consecutive integer: 6
The second consecutive integer: 8