Build and solve the following inequality: *
Ten less than the product of a number and negative four is less than or equal to negative six.
x ≤ - 4
x ≥ - 1
x ≤ 16
x ≥ 4

Question

Build and solve the following inequality: *
Ten less than the product of a number and negative four is less than or equal to negative six.
  x ≤ - 4
 x ≥ - 1
 x ≤ 16
 x ≥ 4

zeronknight · Answer

@Luigi0210

luigi0210 · Answer

Have you tried writing it out?

zeronknight · Answer

I don't know how to even write this out, I was never good at word problems with inequalities.

zeronknight · Answer

All I know is there is <_ a 10 and a  -4

luigi0210 · Answer

At least you understand some of the wording (:

"less than" meaning subtraction 
"product of" meaning multiplication 
"less than or equal to" meaning $\le$ 

Putting them together: 

$\large -4x-10 \le -6 $

luigi0210 · Answer

Think you can solve it from here?

zeronknight · Answer

add 10 to both sides so 10 cancels out 4 turns into 6 and 6 turns in 4

zeronknight · Answer

Do i need to divide?

luigi0210 · Answer

Oh, and when dealing with "less than," you have to reverse the order of the numbers 

and correct, now you're just left with $\large -4x \le 4 $ 

and to get x alone, yes, you'll need to divide.

zeronknight · Answer

so 4 / 4 = 1 But since 4 is negative  1 becomes negative .

zeronknight · Answer

We need to flip the sign again, right?

luigi0210 · Answer

right (:

zeronknight · Answer

So X >_ 1

zeronknight · Answer

-1*

luigi0210 · Answer

And you got bingo :D

zeronknight · Answer

Alright, thanks for your help! C: