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Counting question
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The number of ways in which \(3\) numbers are chosen at random from \(\{1,2,3,\cdots ,10\}\) without replacement such that minimum is \(3\) or maximum is \(7\) is ?
So you have to choose 3 and 7 definitely, and so you get to choose among 4, 5, 6 in the middle. {3, 4, 7} {3, 5, 7} {3, 6, 7}
no,no it is 3 \(\huge or \) 7
That's OK. We still had to calculate that.\[|A \cup B| = |A| + |B| - |A \cap B|\]We just calculated the third part.
ok i get that
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You can similarly calculate \(|A|\) and \(|B|\).
\(\large A=\left(\dbinom{8}{3}-\dbinom{7}{3}\right)\) \(\large B=\left(\dbinom{7}{3}-\dbinom{6}{3}\right)\) is this correct ?
yes
thnks
better represented as 7C2 and 6C2 but it's the same
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