Question

I need somebody to chack..i keep on getting the wrong ONE -.-

Answer 1

Your question?

@AloneS

Answer 2

FOR THIS question i keep on getting this onebut my choices don't match >.>x + 5y - 10 = 0
x = 2y - 8
and i get 5x=2-y

Answer 3

So are you solving for \(x\) and \(y\)?

@AloneS

Answer 4

Yea


For the following system, use the second equation to make a substitution for x in the first equation.

x + 5y - 10 = 0
x = 2y - 8

What is the resulting equation in simplest form?
-3y - 18 = 0
3y - 18 = 0
7y - 18 = 0

Answer 5

Okay. I can help :)

Answer 6

Let me get my work.

Answer 7

THANKS :)

Answer 8

Okay.

So the first equation is \(x + 5y - 10 = 0\)

And the second equation is \(x = 2y - 8\)

I am simply rewriting the equations of the problem :)

Answer 9

Now, in the problem, they want us to use the second equation in order to get the solution for the first equation, which is, \(x + 5y - 10 = 0\)

Answer 10

So for x we want to plug in \(2y - 8\)

Answer 11

Doing that, we should have, \(2y - 8 + 5y - 10 = 0\)

Answer 12

Solving... \(2y + 5y = 7y\)

Answer 13

Continuing to solve... \(-8 - 10 = -18\)

Answer 14

So... finally, the equation in the simplest form would be \(7y - 18 = 0\)

Answer 15

Understand? :)

@AloneS

Answer 16

umm wai tlet me see it again