Sec^2x-1=0. Solve trigonometric equation

Question

Sec^2x-1=0.    Solve trigonometric equation

mathmale · Answer

Please take just a little extra time and write the trig function properly:$$\sec^2 x$$ or |dw:1454036078972:dw|

mathmale · Answer

$$\sec^2x$$

mathmale · Answer

You have $$\sec^2x-1=0$$ and are asked to find values of the angle, x, that satisfy this equation.  Have you considered what you might do next?

anonymous · Answer

Add 1

tkhunny · Answer

$\sec^{2}(x)$

$\left(\sec(x)\right)^{2}$

Several options that exude clarity.

mathmale · Answer

Supposing we were to add 1 to both sides of this equation.   What would happen, and would this result be any easier to solve?  What would the next step be?

anonymous · Answer

Sec^2x=1.   Then you square both sides??

anonymous · Answer

Directions say solve each equation over 0,2pi with the square root method. All answers must be exact in terms of pi.

tkhunny · Answer

You should probably consider factoring the Difference of Squares.

Remember this?  $x^{2} - 1 = 0 \implies (x+1)(x-1) = 0$

anonymous · Answer

Ohhhh ok

anonymous · Answer

But it says solve each equation with square root method

mathmale · Answer

The equation we're discussing is    x^2-1=0.
This is equivalent to x^2=1.

Take the sqrt of both sides, remembering to write in a "plus or minus" sign on one side.