please help!! asap !! fan and medal !! 1.)-(10)^-1 -1/10 -1/-1^10 1/10 10 2.)1/c^-5 c^5 5c -c^5 -5/c 3.)what is the value of y^-5/x^-3 for x=2 and y=-4? 10/3 128 -1/128 -128
the numbers written below each questions, are they options for the answers like A B C D?
yes
i have a couple questions but im only asking 3 at a time
ill go ahead and type the rest..
ok for question 1. do you know that 10^-n = 1/10^n
im confused on all of it thats why im asking for help...
isnt 1 a ?
yeah
wait have you done the questions already or do you need me to explaiN?
i havnt done them
oh ok but for Q1 you are right
For question 2 it is 1/c^-5. To get rid of this negative sign , as in make this power '-5' positive, we need to bring it to the numerator. (note that if this negative power were the numerator you would bring it to the denominator). So 1/c^-5=1*c^5/1=c^5 Get it?
Anyways for the last question again, like the second question, you want to make the powers positive. So you bring them to the numerator or denominator. And you would get x^3/y^5. Subbstitute in the values of x and y and you should get your answer :D
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