What is the equation of y = x^3 with the given transformations?
- Vertical stretch by a factor of 3
- Horizontal shift 4 units to the right
- Vertical shift 3 units down

Question

What is the equation of  y = x^3 with the given transformations?
- Vertical stretch by a factor of 3
- Horizontal shift 4 units to the right
- Vertical shift 3 units down

ltrout · Answer

So far this is what I have: y = 3(x-4)^3. Stretched vertically by 3 and 4 units to the right

anonymous · Answer

yeah thats right now just subtract by 3 for a vertical shift down

ltrout · Answer

So it would be y = 3(x-4)^3 - 3?

anonymous · Answer

$$y = 3(x-4)^3 -3$$
yep lol

ltrout · Answer

Okay lol figured. Was overthinking it :P. Thanks :)

anonymous · Answer

good looks for the medal

anonymous · Answer

a vertical stretch (multiply the function by 3): y = 3x^3 
horizontal shift of 4 units to the right (subtract 4 units from the x): y = 3(x - 4)^3 
Vertical shift 3 units down (subtract 3 units from the function): y = 3(x - 4)^3 - 3

ltrout · Answer

@tburn25  or @Marygirl21  can you guys help on one more?

anonymous · Answer

sure