Question

@skullpatrol Can you please help me???

Answer 1

He is currently busy right now....helping @annah.bee

Answer 2

Do you think you could help me?

Answer 3

Hmmm.....I'm not good at this stuff...hehe

Answer 4

Ohh, okay, that's alright, I'll just wait for @skullpatrol.c:

Answer 5

Q1: If x-2 is a factor, then x=2 is a solution to the poly. Just sub the options back in and check.

Answer 6

Ok, I'll tell him you are waiting....

Answer 7

Okay, thank you.

Answer 8

Q2: Look up complex conjugate

Answer 9

@skullpatrol

Answer 10

I meant to say that I think the first one is option B.

Answer 11

If x = - 2, then (-2)^3+4*(-2)^2 + (-2) -6 = 0 ?

Answer 12

I'm pretty sure that isn't the right way to do it.

Answer 13

I agree with Redcan :-)

Answer 14

Ohh, I'm sorry @Redcan I was confused.

Answer 15

Wait, so would that make it A?

Answer 16

So, is it A or B?

They both have "2" in them, but I was thinking A because the negative sign.

Answer 17

@Redcan or @skullpatrol

Answer 18

(x-2)=0 is x=2

Answer 19

(x+2)=0 if x=?

Answer 20

So, A?

Answer 21

I just wanna make sure I'm getting the correct sign

Answer 22

You want x=-2? So then (x+2)=0

Answer 23

I'm confused lol.

Is it option A or B?

Answer 24

OHH, I think I see what you're saying, if I want x=-2 it would be option B, x+2?

Answer 25

yes

Answer 26

Thank you!

What about the other question?

Answer 27

Complex conjugate

Answer 28

How do you do that?

Answer 29

I feel stupid because I feel like I should know this.

Answer 30

Complex solutions always appear in pairs, a+ib and a-ib.

Answer 31

@Redcan Would it be option A?

a-ib - 3-i

Answer 32

\[3 \pm 4i\]

Answer 33

D?

Answer 34

@Redcan

Answer 35

@Redcan Was I correct?