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Need help with angles, please
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A. 7° B. 83° C. 99° D. 9°
okay so you know what DCB is, 90 and that it is made up of three angles, DCE, ECA, and BCA. You also know that DCE is 37 degrees so ECA + BCA must equal 90-37.
90-37=53 Now you are given two of three angles in triangle BAC. angle ABC is 90 degrees and BAC is 46 degrees. Now the angles of a triangle must add up to 180 so that is angle BCA. Then subtract angle BCA from 53 and that is angle ECA
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yes
Okay so an isosceles triangle has two equal sides and angles. Given the information you can find angle SQP by adding angle SPQ and QSP and subtracting that from 180. You can then figure out angle SQR by subtracting 36 from 180 and dividing by two. Add together SQP and SQR and you get PQR
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