Question

HELP WILL FAN AND MEDAL!:)
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 5 = −5/7 (x – 1); (1, –5)

Answer 1

Perpendicular lines have opposite slope, flip the fraction and multiply by -1 to find the slope of the new line.

Answer 2

Can you explain a little more please?

Answer 3

@iGreen

Answer 4

I think your equation is missing something..check back at the question..is there an 'x' in it?

Answer 5

it says 4+5=-5/7(x-1) (1,-5)

Answer 6

Oh wait, nevermind.

y + 5 = -5/7(x - 1)

This equation is in point-slope form:

y - y1 = m(x - x1)

Where 'm' is the slope and (x1, y1) is a point on the line.

Answer 7

okay. thanks

Answer 8

?

What did you come up with?

Answer 9

The slope here is -5/7, so flip the fraction and multiply by 1 to find the perpendicular line's slope.

Answer 10

multiply by -1*

Answer 11

so you would do -7/5*-1?

Answer 12

Correct!

Answer 13

would that be for all perpendicular equations or just this one in particular?:)

Answer 14

@iGreen

Answer 15

@iGreen i got 7/5... so how would I write that for my answer? like how would i put that in equation form

Answer 16

Okay, we have the point and the slope, so all we have to do is plug it back into point-slope form.

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf m\) is the slope and \(\sf (x_1, y_1)\) is a point on the line.

Just plug in the given information..we already found the slope, and the point is given in the question.

Answer 17

so i would write it as y-7/5x-1? I think thats right..?

Answer 18

y+7/5x-1 sorry messed up there

Answer 19

ugh thats supposed to be an equals sign sorry lol

Answer 20

Does it want the equation in slope-intercept form or point-slope form?

Just plug in the values..don't change anything else.

Answer 21

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf m\) is the slope and \(\sf (x_1, y_1)\) is a point on the line.

In this case:

\(\sf m = \dfrac{7}{5}\)

And:

\(\sf x_1 = 1\)
\(\sf y_1 = -5\)

Answer 22

So what do we have?