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Mathematics 18 Online
OpenStudy (anonymous):

WILL MEDAL

OpenStudy (anonymous):

What is the area of the figure? https://static.k12.com/calms_media/media/1567000_1567500/1567393/1/c4468a1690d478712d6a5a1c88192858380e4b51/MS_IMB-1401012-1100712.jpg A. 90 millimeters squared B. 110 millimeters squared C. 130 millimeters squared D. 180 millimeters squared

OpenStudy (studygurl14):

You have two trapezoids there. Find the area of the them and then add the areas together. Area of Trapezoid: \(\Large(\frac{b_1+b_2}{2})h\) b1 = lenght of base 1 b2 = length of base 2 h = height

OpenStudy (anonymous):

I dont know how to find the base and the hight on this question

OpenStudy (anonymous):

@StudyGurl14

OpenStudy (studygurl14):

Okay, sorry, ignore that. There's a much easier way to do it. Find the area of the square, and then subtract the area of the triangle. See pic

OpenStudy (anonymous):

what is the hight of the triangle?

OpenStudy (studygurl14):

11 -7

OpenStudy (anonymous):

is the hight 4

OpenStudy (anonymous):

@StudyGurl14

OpenStudy (anonymous):

IS THE HIGHT 4 BECAUSE 11-7=4

OpenStudy (anonymous):

hello? @StudyGurl14

OpenStudy (studygurl14):

yes

OpenStudy (anonymous):

tahnks

OpenStudy (anonymous):

is the answer 90?

OpenStudy (anonymous):

thats what i got

OpenStudy (studygurl14):

yep, great job!

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