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Mathematics 16 Online
OpenStudy (anonymous):

A standard deck of cards has 4 suits (hearts, diamonds, spades, and clubs) each with 13 cards in it (ace -10, jack, queen, and king). The number cards are 2-10. When drawing a card randomly from a deck, what is the probability that it will be either a diamond or a number card?

OpenStudy (faiqraees):

all diamonds + number cards -------------------------- Total Cards

OpenStudy (anonymous):

13+9/100?

OpenStudy (anonymous):

@FaiqRaees

OpenStudy (anonymous):

So it's 22/100? Or did I get the equation numbers wrong? I'm confused at how it's worded.

OpenStudy (faiqraees):

there are four suits in which number cards are present. Since we are counting the whole diamonds, only three suits are left which have numbered cards. So how many numbered cards are there in total?

OpenStudy (anonymous):

39?

OpenStudy (faiqraees):

numbered cards * 3 suits

OpenStudy (anonymous):

27?

OpenStudy (anonymous):

Sorry I'm so confused right now

OpenStudy (faiqraees):

yes

OpenStudy (faiqraees):

and if you add all the diamond cards?

OpenStudy (faiqraees):

27+?

OpenStudy (anonymous):

40?

OpenStudy (faiqraees):

and total number of cards are?

OpenStudy (anonymous):

48?

OpenStudy (faiqraees):

total number of cards in a suit = 13 Suits presents = 4

OpenStudy (anonymous):

I thought you said to not count the diamonds? Does that mean that the total is 52? or is it 61 if I add the numbered cards?

OpenStudy (anonymous):

Can someone explain I'm honestly so confused.

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