hey! A medal and a fan awarded for whoever can help me solve this! y=2x+5, y-4x=-2 I have to do this equation through graphing, please help!
have you graphed it?
ah, im stuck on the graphing part....
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okay, these are both linear equations: no exponents on \(x\) or \(y\). Here's my procedure for easy graphing of linear equations. 1) set \(x=0\) and find the value of \(y\). Put a mark at \((0,y)\). 2) set \(y = 0\) and find the value of \(x\). Put a mark at \((x,0)\). Now draw a straight line through those points. Congratulations, you just graphed that equation. Do both equations and figure out the coordinates of the point where they intersect. That is your solution.
So if y=2x+5, y-4x=-2 you need to get x and y on different sides... the first problem is fine but the second you need to move x to the other side by adding it so one side cancels out and x would be with -2. After doing this you would get y=4x-2 The equation you are currently using is y=mx+b. So to graph b is your y intercept so this number would go on your y axis and from there m is your slope. So you take the slope over 1 which would mean y=4x-2 has a slope of 4/1. To graph this starting from b you would go up 4 and to the right 1 or down 4 and to the left 1. And do the same thing with your other equation.
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