Question

For each linear equation write the slope of a line perpendicular to the given line.

3x+5y=-15

Answer 1

so hmm what would be the slope of \(\bf 3x+5y=-15?\)

Answer 2

There is also
y=\[y=\frac{ 1 }{ 5 }x-4\]

Answer 3

3x

Answer 4

well.. if you were to solve for "y" on 3x+5y=-15, what would it look like?

Answer 5

umm -3/5

Answer 6

what do you mean -3/5?

Answer 7

the slope would be -3/5

Answer 8

ok... .well.. then the slope of a line PERPENDICULAR to that one
will have the NEGATIVE RECIPROCAL of that one

that is \(\bf slope=\cfrac{a}{{\color{blue}{ b}}}\qquad negative\implies -\cfrac{a}{{\color{blue}{ b}}}\qquad reciprocal\implies - \cfrac{{\color{blue}{ b}}}{a}\)

Answer 9

Oh! so -5/3?

Answer 10

\(\bf -\cfrac{3}{{\color{blue}{ 5}}}\qquad negative\implies +\cfrac{3}{{\color{blue}{ 5}}}\qquad reciprocal\implies \cfrac{{\color{blue}{ 5}}}{3}\)

Answer 11

negative * negative = +

Answer 12

Oh okay

Answer 13

Thank you

Answer 14

yw