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OpenStudy (saadi101):
Solve using substitution: -3x + y = 1 and 4x + y = 8. Put your answer in coordinate form.
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OpenStudy (jtug6):
Solve for one variable of either equation. How about the first? what does y equal for the first equation?
OpenStudy (saadi101):
I'm not sure how I go about doing any of this. Could you walk me through it I have 3 more questions like it
OpenStudy (jtug6):
Well solve for y for eqn 1. Add 3x to both sides perhaps? What does that give you for -3x + y = 1 if you add 3x to both sides?
OpenStudy (saadi101):
I don't understand explaining this in text, could you write out what your doing?
OpenStudy (jtug6):
\[-3x + y = 1\]
and we're adding 3x to both sides
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OpenStudy (jtug6):
\[-3x + 3x + y = 1 + 3x\] right?
OpenStudy (saadi101):
okay, yea
OpenStudy (jtug6):
so now you have \[y = 1 + 3x \] because -3x + 3x cancel right?
OpenStudy (saadi101):
right
OpenStudy (jtug6):
Now you know what y is, right? Well we have a 2nd equation which is:
\[4x + y = 8\]
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OpenStudy (jtug6):
So, if we know what y is what can we do to that equation?
OpenStudy (jtug6):
We're doing substitution, yes?
OpenStudy (saadi101):
right
OpenStudy (jtug6):
We know that y was equal to 1 + 3x so y has a new meaning too. It isn't just y anymore. We're substitution the what into y for \[4x + y = \]
OpenStudy (jtug6):
err \[4x + y = 8\]
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OpenStudy (saadi101):
okay....
OpenStudy (jtug6):
Ok here i'll try to make it easier xD|dw:1454818354836:dw|
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