Question

question on optics

Answer 1

the red part, why?

Answer 2

Because the angles are small, so
\(\dfrac{h'}{f_E}=\tan \theta_E \approx \theta_E\) and
\(\dfrac{h}{f_O}=\tan \theta_O \approx \theta_O\)

Answer 3

ofcourse I know that! @Vincent-Lyon.Fr
I am saying, "can't you see that its not the full triangle

Answer 4

Explain why thetaE=h(prime)/fE???

Answer 5

and also the denominator respectively!

Answer 6

The triangles are here in green.

Answer 7

Cleared!
You saved my day again @Vincent-Lyon.Fr
Salute

Answer 8

Thank you so much @Vincent-Lyon.Fr