Question

Please Help??!!!

Answer 1

\[\frac{ 6x ^{4}-2x ^{3}-13x-7 }{ 3x+8 }\]

Answer 2

=−68x+8

Answer 3

How did you do that?

Answer 4

$6x\cdot\:4-2x\cdot\:3-13x-73x+8$6x· 4−2x· 3−13x−73x+8


$\mathrm{Multiply\:the\:numbers:}\:4\cdot\:6=24$Multiply the numbers: 4· 6=24

$=24x-2\cdot\:3x-13x-73x+8$=24x−2· 3x−13x−73x+8



$\mathrm{Multiply\:the\:numbers:}\:2\cdot\:3=6$Multiply the numbers: 2· 3=6

$=24x-6x-13x-73x+8$=24x−6x−13x−73x+8

Answer 5

that is how

Answer 6

Okay Thank you

Answer 7

np

Answer 8

need any more help>?

Answer 9

gtg byeee