Question

Find the value of 53^3 using the identity (x+y)^3=x^3+3x^2y+3xy^2+y^2
Hint 53^3 =(50+3)^3; therefore, x=50, and y=3
I do not get this

Answer 1

replace x with 50 and y with 3

Answer 2

write x^3+3x^2y+3xy^2+y^2
but with 50 for x and 3 for y instead

Answer 3

how much to you understand and what part is confusing ?

Answer 4

(50+3^3= 1*50^3 + 3(50)^2(3) + 3(50)(3)^2 + 1*3^3=
125,000+22500+1350+27=
148,877

Answer 5

@freckles

Answer 6

@phi ??

Answer 7

yes. and you can use a calculator and compute 53^3 directly. You should get the same answer

Answer 8

okay thank you!!