Hi this question really confused me. I tried to answer it but I got it wrong can anyone help?

What is the side length, if the area of the square is:

9. 64x sqrt(y)

8x^2 fourthroot y

Question

Hi this question really confused me. I tried to answer it but I got it wrong can anyone help?

What is the side length, if the area of the square is:

9. 64x sqrt(y)

 8x^2 fourthroot y

katie_rogers101 · Answer

That was my wrong answer

mathstudent55 · Answer

Is 9 part of the area?

mathstudent55 · Answer

If 9 is not part of the problem, then you have:

$A = 64x\sqrt y$

$s^2 = 64x \sqrt y$

$s = \sqrt{64x \sqrt y} $

$s = \sqrt {64} \sqrt x \sqrt{\sqrt y}  $

$s = 8 \sqrt x \sqrt[4] y$

It looks like your only mistake was that you squared x instead of taking its square root.

katie_rogers101 · Answer

oh okay well thank you. I thought I was messing up on the 4throot thing