Question

Find the perimeter of a quadrilateral with vertices at C (−1, 2), D (−2, −1), E (2, −2), and F (1, 1). Round your answer to the nearest hundredth when necessary.

10.92 units
12.68 units
13.43 units
18.27 units

Answer 1

@dan815 @Michele_Laino @johnweldon1993

Answer 2

@KendrickLamar2014 @jabez177 @imqwerty

Answer 3

@Data_LG2

Answer 4

Hint* If I give you 2 points...say (2,1) and (9,3)

How would you find the distance between them?

Answer 5

using the distance formula @johnweldon1993

Answer 6

I would suggest that you plot your points first to get a better understanding: http://i.imgur.com/RgOFnY5.png

Next, like what john said, have to find the length CD, CF, FE and DE using the distance formula. That is from point C to D, C to F, F to E and D to E, repsectively.

Distance Formula is:
\(\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)}\), where \(\sf (x_1, y_1)\) is your first point and \(\sf (x_2, y_2)\) is your second point.

Answer 7

Right

So now, with your given points, we merely use the distance formula to find the distance between adjacent points

Edit: Data beat me to it lol

Answer 8

Sorry , I was typing but OS doesn't show I am typing x.x

Answer 9

so it would be 7.2802? @Data_LG2 @johnweldon1993

Answer 10

which points did you use to get that value?

Answer 11

After doing them all I got 11.39 which isn't one of the choices! @Data_LG2

Answer 12

let's do it step by step, what value did you get for the length of CD ?

Answer 13

3.162

Answer 14

right, now what did you get for CF?

Answer 15

2.236

Answer 16

and for FE and DE?

Answer 17

FE= 3.162
DE= 4.123

Answer 18

It's B, 12.68
Thank you!

Answer 19

lol welcome! :D