DEAR GOD SOMEONE HALP MEH '-' PLZ HALP MEH....
Find the x-intercepts of the parabola with vertex (-3,16) and y-intercept (0,-20). Write your answer in this form: (x,y),(x,y). If necessary, round to the nearest hundredth.
*Help
nope srry im in 6th
ANYBODY... please...
im not god but i might be able to help
please
with wht??
ok one sec
find the x intercepts of the parabola with vertex (-5,80) and y intercept (0,-45). write answer in this form: (x,y),(x,y)
about it im really sry
anyone able to help?
hi i am rap god but i can help you
good enough
ill take any help i can get
okay let me think
ok ;)
tbh i am in no mood to do all this
so no help? :(
i will medal and fan :(
): i need to be in mood then only i can help can u do something to bring that mood
?
sure
anyone please help me
find the x intercepts of the parabola with vertex (-5,80) and y intercept (0,-45). write answer in this form: (x,y),(x,y)
Hi Welcome to Openstudy! First let's make an equation for the parabola. Vertex form of a parabola is \(\sf y = a(x-h)^2+k\), where (h,k) is the vertex. From the given values on your question: you have vertex (-3,16) and y-intercept (0,-20) Plug the vertex in the equation, you'll get: \(\sf y=a(x+3)^2+16\) Using the y-int point, find the value of "a" : \(\sf -20=a(0+3)^2+16\) Can you do that for now? Evaluate the equation and find the value of "a"
so i distribute the a?
No need to do that. Remove the brackets first. what is \(\sf (0+3)^2\)?
9
right, so you have: \(\sf -20=9a+16\) can you solve "a" now?
do i add 20 to both sides then? or like subtract 16
subtracting both sides by 16 is easier (:
-36
right. now you have: -36 = 9a now, divide both sides by 9, what will you get?
a= ?
a=-4?
a=4
but i need it like this (x,y),(x,y)
yes, a= -4 . We are not done yet. We are only setting up the equation to solve for the values of x-intercepts. So the equation for the parabola is \(\sf y=-4(x+3)^2+16\) TO get the x-interepts, we need to set y=0, so the points you will have should be (x,0) form. Now let's plug in y=0 in the equation and solve for the value of "x" \(\sf 0=-4(x+3)^2+16\) What is the first thing you would do to solve for x?
@shallowgam3r are you still there?
I guess he already left for no reason. For future reference, when you will solve for the value of x, you should end up getting two values for it. Goodluck!
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