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Geometry Help
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this isn't Geo, it's hell
Exactly what I thought
im in alg 2
Ok, thanks anyways
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hint: since BCD is a right triangle, we can apply the theorem of Pitagora, so we get: \[\Large C{D^2} + {8^2} = B{C^2}\] furthermore, also ABC is a right triangle, so I can apply the second theorem of Euclide, so I can write: \[\Large B{D^2} = AD \times DC\] Both of the above equations solve the problem
So for the first one x^2+8^2=y^2? @Michele_Laino
yes!
and the second one can be rewritten as follows: \(64=15x\)
thanks
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